Base | Representation |
---|---|
bin | 10100000010010011110… |
… | …010110100011110111011 |
3 | 11212121221101010201022221 |
4 | 110002103302310132323 |
5 | 140024311442421033 |
6 | 2532305215224511 |
7 | 201322046212051 |
oct | 24022362643673 |
9 | 4777841121287 |
10 | 1376869107643 |
11 | 490a21797527 |
12 | 1a2a1a818137 |
13 | 9cab86a9013 |
14 | 4a8d85a81d1 |
15 | 25c375e712d |
hex | 14093cb47bb |
1376869107643 has 4 divisors (see below), whose sum is σ = 1377212727600. Its totient is φ = 1376525487688.
The previous prime is 1376869107629. The next prime is 1376869107661. The reversal of 1376869107643 is 3467019686731.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1376869107643 - 213 = 1376869099451 is a prime.
It is a super-2 number, since 2×13768691076432 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1376869107623) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 171803968 + ... + 171811981.
It is an arithmetic number, because the mean of its divisors is an integer number (344303181900).
Almost surely, 21376869107643 is an apocalyptic number.
1376869107643 is a deficient number, since it is larger than the sum of its proper divisors (343619957).
1376869107643 is an equidigital number, since it uses as much as digits as its factorization.
1376869107643 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 343619956.
The product of its (nonzero) digits is 27433728, while the sum is 61.
The spelling of 1376869107643 in words is "one trillion, three hundred seventy-six billion, eight hundred sixty-nine million, one hundred seven thousand, six hundred forty-three".
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