1377582067153 has 4 divisors (see below), whose sum is σ = 1377825504880. Its totient is φ = 1377338629428.

The previous prime is 1377582067073. The next prime is 1377582067159. The reversal of 1377582067153 is 3517602857731.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1377582067153 - 2¹³ = 1377582058961 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1377582067094 and 1377582067103.

It is not an unprimeable number, because it can be changed into a prime (1377582067159) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 121710375 + ... + 121721692.

It is an arithmetic number, because the mean of its divisors is an integer number (344456376220).

Almost surely, 2^{1377582067153} is an apocalyptic number.

It is an amenable number.

1377582067153 is a deficient number, since it is larger than the sum of its proper divisors (243437727).

1377582067153 is an equidigital number, since it uses as much as digits as its factorization.

1377582067153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 243437726.

The product of its (nonzero) digits is 7408800, while the sum is 55.

The spelling of 1377582067153 in words is "one trillion, three hundred seventy-seven billion, five hundred eighty-two million, sixty-seven thousand, one hundred fifty-three".