Base | Representation |
---|---|
bin | 1000000010001000001… |
… | …1111001001111000001 |
3 | 111012020011220201012111 |
4 | 2000202003321033001 |
5 | 4230121130242211 |
6 | 143222345455321 |
7 | 12654012020200 |
oct | 2004203711701 |
9 | 435204821174 |
10 | 138010399681 |
11 | 535912aaa60 |
12 | 228b74a1541 |
13 | 100256193bb |
14 | 69732bd237 |
15 | 38cb215421 |
hex | 20220f93c1 |
138010399681 has 12 divisors (see below), whose sum is σ = 175137502320. Its totient is φ = 107540570760.
The previous prime is 138010399661. The next prime is 138010399699. The reversal of 138010399681 is 186993010831.
It is not a de Polignac number, because 138010399681 - 213 = 138010391489 is a prime.
It is a super-2 number, since 2×1380103996812 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (49).
It is not an unprimeable number, because it can be changed into a prime (138010399621) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 128023951 + ... + 128025028.
It is an arithmetic number, because the mean of its divisors is an integer number (14594791860).
Almost surely, 2138010399681 is an apocalyptic number.
138010399681 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
138010399681 is a deficient number, since it is larger than the sum of its proper divisors (37127102639).
138010399681 is a wasteful number, since it uses less digits than its factorization.
138010399681 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 256049004 (or 256048997 counting only the distinct ones).
The product of its (nonzero) digits is 279936, while the sum is 49.
The spelling of 138010399681 in words is "one hundred thirty-eight billion, ten million, three hundred ninety-nine thousand, six hundred eighty-one".
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