Base | Representation |
---|---|
bin | 11001101101001110… |
… | …11010011011101001 |
3 | 1022121211101202221201 |
4 | 30312213122123221 |
5 | 211231102002213 |
6 | 10201251404201 |
7 | 666002202463 |
oct | 146647323351 |
9 | 38554352851 |
10 | 13801203433 |
11 | 5942468456 |
12 | 2811bb3661 |
13 | 13bc386584 |
14 | 94cd29133 |
15 | 55b9656dd |
hex | 3369da6e9 |
13801203433 has 4 divisors (see below), whose sum is σ = 13804091280. Its totient is φ = 13798315588.
The previous prime is 13801203421. The next prime is 13801203473. The reversal of 13801203433 is 33430210831.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33430210831 = 947 ⋅35301173.
It is a cyclic number.
It is not a de Polignac number, because 13801203433 - 25 = 13801203401 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13801203473) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1436743 + ... + 1446316.
It is an arithmetic number, because the mean of its divisors is an integer number (3451022820).
Almost surely, 213801203433 is an apocalyptic number.
It is an amenable number.
13801203433 is a deficient number, since it is larger than the sum of its proper divisors (2887847).
13801203433 is an equidigital number, since it uses as much as digits as its factorization.
13801203433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2887846.
The product of its (nonzero) digits is 5184, while the sum is 28.
The spelling of 13801203433 in words is "thirteen billion, eight hundred one million, two hundred three thousand, four hundred thirty-three".
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