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1380225600553 = 1781189741209
BaseRepresentation
bin10100000101011011110…
…110110100110000101001
311212221121021222020000011
4110011123312310300221
5140103200223204203
62534022240411521
7201501164013502
oct24053366646051
94787537866004
101380225600553
11492394407308
121a35b6916ba1
13a0201baabb7
144ab3628bba9
1525d8210876d
hex1415bdb4c29

1380225600553 has 4 divisors (see below), whose sum is σ = 1461415341780. Its totient is φ = 1299035859328.

The previous prime is 1380225600493. The next prime is 1380225600557. The reversal of 1380225600553 is 3550065220831.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 965371096089 + 414854504464 = 982533^2 + 644092^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1380225600553 is a prime.

It is a super-3 number, since 3×13802256005533 (a number of 37 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (1380225600557) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40594870588 + ... + 40594870621.

It is an arithmetic number, because the mean of its divisors is an integer number (365353835445).

Almost surely, 21380225600553 is an apocalyptic number.

It is an amenable number.

1380225600553 is a deficient number, since it is larger than the sum of its proper divisors (81189741227).

1380225600553 is an equidigital number, since it uses as much as digits as its factorization.

1380225600553 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 81189741226.

The product of its (nonzero) digits is 216000, while the sum is 40.

The spelling of 1380225600553 in words is "one trillion, three hundred eighty billion, two hundred twenty-five million, six hundred thousand, five hundred fifty-three".

Divisors: 1 17 81189741209 1380225600553