Base | Representation |
---|---|
bin | 10100000101011100001… |
… | …001111000010011010001 |
3 | 11212221121122101000012001 |
4 | 110011130021320103101 |
5 | 140103203013031133 |
6 | 2534022535434001 |
7 | 201501254330050 |
oct | 24053411702321 |
9 | 4787548330161 |
10 | 1380230595793 |
11 | 492397209305 |
12 | 1a35b8525901 |
13 | a0202c3976a |
14 | 4ab36bcc397 |
15 | 25d8279387d |
hex | 1415c2784d1 |
1380230595793 has 8 divisors (see below), whose sum is σ = 1615879722240. Its totient is φ = 1154199801120.
The previous prime is 1380230595791. The next prime is 1380230595827. The reversal of 1380230595793 is 3975950320831.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1380230595793 - 21 = 1380230595791 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1380230595791) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2404582633 + ... + 2404583206.
It is an arithmetic number, because the mean of its divisors is an integer number (201984965280).
Almost surely, 21380230595793 is an apocalyptic number.
It is an amenable number.
1380230595793 is a deficient number, since it is larger than the sum of its proper divisors (235649126447).
1380230595793 is an equidigital number, since it uses as much as digits as its factorization.
1380230595793 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4809165887.
The product of its (nonzero) digits is 6123600, while the sum is 55.
The spelling of 1380230595793 in words is "one trillion, three hundred eighty billion, two hundred thirty million, five hundred ninety-five thousand, seven hundred ninety-three".
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