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1380250900043 = 3973476702519
BaseRepresentation
bin10100000101011101010…
…111010101011001001011
311212221200001120120101022
4110011131113111121023
5140103223212300133
62534024542543055
7201501622034111
oct24053527253113
94787601516338
101380250900043
114923a7717184
121a3603297a8b
13a02071c8502
144ab39795ab1
1525d84454998
hex1415d5d564b

1380250900043 has 4 divisors (see below), whose sum is σ = 1383727602960. Its totient is φ = 1376774197128.

The previous prime is 1380250900001. The next prime is 1380250900087. The reversal of 1380250900043 is 3400090520831.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1380250900043 - 228 = 1379982464587 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1380250899976 and 1380250900012.

It is not an unprimeable number, because it can be changed into a prime (1380250900243) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1738350863 + ... + 1738351656.

It is an arithmetic number, because the mean of its divisors is an integer number (345931900740).

Almost surely, 21380250900043 is an apocalyptic number.

1380250900043 is a deficient number, since it is larger than the sum of its proper divisors (3476702917).

1380250900043 is an equidigital number, since it uses as much as digits as its factorization.

1380250900043 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3476702916.

The product of its (nonzero) digits is 25920, while the sum is 35.

The spelling of 1380250900043 in words is "one trillion, three hundred eighty billion, two hundred fifty million, nine hundred thousand, forty-three".

Divisors: 1 397 3476702519 1380250900043