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13811418553 = 32994186547
BaseRepresentation
bin11001101110011100…
…11000010110111001
31022122112121202110111
430313032120112321
5211241210343203
610202254344321
7666155056252
oct146716302671
938575552414
1013811418553
1159482051a9
1228154bb0a1
1313c152201a
14950427b29
1555c7d226d
hex3373985b9

13811418553 has 4 divisors (see below), whose sum is σ = 13815608400. Its totient is φ = 13807228708.

The previous prime is 13811418541. The next prime is 13811418587. The reversal of 13811418553 is 35581411831.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35581411831 = 75083058833.

It is a cyclic number.

It is not a de Polignac number, because 13811418553 - 25 = 13811418521 is a prime.

It is a super-2 number, since 2×138114185532 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13811418503) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2089975 + ... + 2096572.

It is an arithmetic number, because the mean of its divisors is an integer number (3453902100).

Almost surely, 213811418553 is an apocalyptic number.

It is an amenable number.

13811418553 is a deficient number, since it is larger than the sum of its proper divisors (4189847).

13811418553 is an equidigital number, since it uses as much as digits as its factorization.

13811418553 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4189846.

The product of its digits is 57600, while the sum is 40.

The spelling of 13811418553 in words is "thirteen billion, eight hundred eleven million, four hundred eighteen thousand, five hundred fifty-three".

Divisors: 1 3299 4186547 13811418553