Search a number
-
+
13815050473 = 71973578639
BaseRepresentation
bin11001101110111000…
…01111000011101001
31022122210110021112001
430313130033003221
5211243123103343
610202504251001
7666230664040
oct146734170351
938583407461
1013815050473
11594a265994
122816770a61
1313c21c41a3
14950ad1557
1555cc9d44d
hex33770f0e9

13815050473 has 4 divisors (see below), whose sum is σ = 15788629120. Its totient is φ = 11841471828.

The previous prime is 13815050429. The next prime is 13815050489. The reversal of 13815050473 is 37405051831.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13815050473 - 29 = 13815049961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13815050413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 986789313 + ... + 986789326.

It is an arithmetic number, because the mean of its divisors is an integer number (3947157280).

Almost surely, 213815050473 is an apocalyptic number.

It is an amenable number.

13815050473 is a deficient number, since it is larger than the sum of its proper divisors (1973578647).

13815050473 is an equidigital number, since it uses as much as digits as its factorization.

13815050473 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1973578646.

The product of its (nonzero) digits is 50400, while the sum is 37.

The spelling of 13815050473 in words is "thirteen billion, eight hundred fifteen million, fifty thousand, four hundred seventy-three".

Divisors: 1 7 1973578639 13815050473