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138299062267 = 547792524673
BaseRepresentation
bin1000000011001101000…
…1000011011111111011
3111012222022002021211101
42000303101003133323
54231214024443032
6143311140512231
712664115430112
oct2006321033773
9435868067741
10138299062267
115371a240483
12229780ab677
1310070377972
14699d780c79
1538e6734de7
hex20334437fb

138299062267 has 4 divisors (see below), whose sum is σ = 138301641720. Its totient is φ = 138296482816.

The previous prime is 138299062229. The next prime is 138299062271. The reversal of 138299062267 is 762260992831.

138299062267 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 138299062267 - 215 = 138299029499 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (138299062067) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1207558 + ... + 1317115.

It is an arithmetic number, because the mean of its divisors is an integer number (34575410430).

Almost surely, 2138299062267 is an apocalyptic number.

138299062267 is a deficient number, since it is larger than the sum of its proper divisors (2579453).

138299062267 is an equidigital number, since it uses as much as digits as its factorization.

138299062267 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2579452.

The product of its (nonzero) digits is 3919104, while the sum is 55.

The spelling of 138299062267 in words is "one hundred thirty-eight billion, two hundred ninety-nine million, sixty-two thousand, two hundred sixty-seven".

Divisors: 1 54779 2524673 138299062267