Base | Representation |
---|---|
bin | 11001110000110000… |
… | …10111111011001001 |
3 | 1022200220010012222110 |
4 | 30320120113323021 |
5 | 211311142043213 |
6 | 10204230212533 |
7 | 666511664031 |
oct | 147030277311 |
9 | 38626105873 |
10 | 13830815433 |
11 | 5958153386 |
12 | 281bab4149 |
13 | 13c5553a76 |
14 | 952c368c1 |
15 | 55e3645c3 |
hex | 338617ec9 |
13830815433 has 4 divisors (see below), whose sum is σ = 18441087248. Its totient is φ = 9220543620.
The previous prime is 13830815417. The next prime is 13830815503. The reversal of 13830815433 is 33451803831.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33451803831 = 3 ⋅11150601277.
It is not a de Polignac number, because 13830815433 - 24 = 13830815417 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13830815391 and 13830815400.
It is not an unprimeable number, because it can be changed into a prime (13830811433) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2305135903 + ... + 2305135908.
It is an arithmetic number, because the mean of its divisors is an integer number (4610271812).
Almost surely, 213830815433 is an apocalyptic number.
It is an amenable number.
13830815433 is a deficient number, since it is larger than the sum of its proper divisors (4610271815).
13830815433 is an equidigital number, since it uses as much as digits as its factorization.
13830815433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4610271814.
The product of its (nonzero) digits is 103680, while the sum is 39.
The spelling of 13830815433 in words is "thirteen billion, eight hundred thirty million, eight hundred fifteen thousand, four hundred thirty-three".
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