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1383348510851 = 5701242650151
BaseRepresentation
bin10100001000010101111…
…111110010000010000011
311220020122221021111120112
4110020111333302002003
5140131044204321401
62535300155301535
7201641444221316
oct24102577620203
94806587244515
101383348510851
1149374719700a
121a412874a8ab
13a05abb97c08
144ad50d2a97d
1525eb637a3bb
hex14215ff2083

1383348510851 has 4 divisors (see below), whose sum is σ = 1383591166704. Its totient is φ = 1383105855000.

The previous prime is 1383348510829. The next prime is 1383348510871. The reversal of 1383348510851 is 1580158433831.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1383348510851 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1383348510851.

It is not an unprimeable number, because it can be changed into a prime (1383348510871) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 121319375 + ... + 121330776.

It is an arithmetic number, because the mean of its divisors is an integer number (345897791676).

Almost surely, 21383348510851 is an apocalyptic number.

1383348510851 is a deficient number, since it is larger than the sum of its proper divisors (242655853).

1383348510851 is an equidigital number, since it uses as much as digits as its factorization.

1383348510851 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 242655852.

The product of its (nonzero) digits is 1382400, while the sum is 50.

The spelling of 1383348510851 in words is "one trillion, three hundred eighty-three billion, three hundred forty-eight million, five hundred ten thousand, eight hundred fifty-one".

Divisors: 1 5701 242650151 1383348510851