138341365171147 has 4 divisors (see below), whose sum is σ = 138341799666720. Its totient is φ = 138340930675576.

The previous prime is 138341365171133. The next prime is 138341365171183. The reversal of 138341365171147 is 741171563143831.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 138341365171147 - 2¹¹ = 138341365169099 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (138341365175147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 216769843 + ... + 217407100.

It is an arithmetic number, because the mean of its divisors is an integer number (34585449916680).

Almost surely, 2^{138341365171147} is an apocalyptic number.

138341365171147 is a deficient number, since it is larger than the sum of its proper divisors (434495573).

138341365171147 is an equidigital number, since it uses as much as digits as its factorization.

138341365171147 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 434495572.

The product of its digits is 5080320, while the sum is 55.

The spelling of 138341365171147 in words is "one hundred thirty-eight trillion, three hundred forty-one billion, three hundred sixty-five million, one hundred seventy-one thousand, one hundred forty-seven".