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13842424833 = 34614141611
BaseRepresentation
bin11001110010001001…
…01010010000000001
31022201200222001002020
430321010222100001
5211322130043313
610205323112053
71000012445466
oct147104522001
938650861066
1013842424833
115963762726
122823972629
1313c7a8a033
149545b966d
155603a9323
hex33912a401

13842424833 has 4 divisors (see below), whose sum is σ = 18456566448. Its totient is φ = 9228283220.

The previous prime is 13842424801. The next prime is 13842424859. The reversal of 13842424833 is 33842424831.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13842424833 - 25 = 13842424801 is a prime.

It is a super-2 number, since 2×138424248332 (a number of 21 digits) contains 22 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (13842424733) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2307070803 + ... + 2307070808.

It is an arithmetic number, because the mean of its divisors is an integer number (4614141612).

Almost surely, 213842424833 is an apocalyptic number.

It is an amenable number.

13842424833 is a deficient number, since it is larger than the sum of its proper divisors (4614141615).

13842424833 is an equidigital number, since it uses as much as digits as its factorization.

13842424833 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4614141614.

The product of its digits is 442368, while the sum is 42.

The spelling of 13842424833 in words is "thirteen billion, eight hundred forty-two million, four hundred twenty-four thousand, eight hundred thirty-three".

Divisors: 1 3 4614141611 13842424833