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13845503617 = 111258682147
BaseRepresentation
bin11001110010100000…
…11001111010000001
31022201220202110101021
430321100121322001
5211323422103432
610205513105441
71000050560521
oct147120317201
938656673337
1013845503617
115965475880
1228249b8281
1313c85c74ba
14954b7b681
155607b6697
hex339419e81

13845503617 has 4 divisors (see below), whose sum is σ = 15104185776. Its totient is φ = 12586821460.

The previous prime is 13845503599. The next prime is 13845503629. The reversal of 13845503617 is 71630554831.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 71630554831 = 116511868621.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13845503617 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13845503417) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 629341063 + ... + 629341084.

It is an arithmetic number, because the mean of its divisors is an integer number (3776046444).

Almost surely, 213845503617 is an apocalyptic number.

It is an amenable number.

13845503617 is a deficient number, since it is larger than the sum of its proper divisors (1258682159).

13845503617 is a wasteful number, since it uses less digits than its factorization.

13845503617 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1258682158.

The product of its (nonzero) digits is 302400, while the sum is 43.

The spelling of 13845503617 in words is "thirteen billion, eight hundred forty-five million, five hundred three thousand, six hundred seventeen".

Divisors: 1 11 1258682147 13845503617