13871035 has 4 divisors (see below), whose sum is σ = 16645248. Its totient is φ = 11096824.

The previous prime is 13871023. The next prime is 13871051. The reversal of 13871035 is 53017831.

13871035 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13871035 - 2¹⁵ = 13838267 is a prime.

It is a super-2 number, since 2×13871035² = 384811223942450, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13870994 and 13871012.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1387099 + ... + 1387108.

It is an arithmetic number, because the mean of its divisors is an integer number (4161312).

Almost surely, 2^13871035 is an apocalyptic number.

13871035 is a deficient number, since it is larger than the sum of its proper divisors (2774213).

13871035 is an equidigital number, since it uses as much as digits as its factorization.

13871035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2774212.

The product of its (nonzero) digits is 2520, while the sum is 28.

The square root of 13871035 is about 3724.3838416576. The cubic root of 13871035 is about 240.2718851643.

Adding to 13871035 its reverse (53017831), we get a palindrome (66888866).

The spelling of 13871035 in words is "thirteen million, eight hundred seventy-one thousand, thirty-five".