Base | Representation |
---|---|
bin | 1100100111101000011001… |
… | …1101100001111010111011 |
3 | 1211010102210121211221022110 |
4 | 3021322012131201322323 |
5 | 3304312000031113024 |
6 | 45302030452423403 |
7 | 2631302304136443 |
oct | 311720635417273 |
9 | 54112717757273 |
10 | 13875000254139 |
11 | 446a399a174a2 |
12 | 1681099617b63 |
13 | 798539c9989b |
14 | 35d7a70cd123 |
15 | 190dc2041629 |
hex | c9e86761ebb |
13875000254139 has 4 divisors (see below), whose sum is σ = 18500000338856. Its totient is φ = 9250000169424.
The previous prime is 13875000254131. The next prime is 13875000254173. The reversal of 13875000254139 is 93145200057831.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 13875000254139 - 23 = 13875000254131 is a prime.
It is a super-3 number, since 3×138750002541393 (a number of 40 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13875000254131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2312500042354 + ... + 2312500042359.
It is an arithmetic number, because the mean of its divisors is an integer number (4625000084714).
Almost surely, 213875000254139 is an apocalyptic number.
13875000254139 is a deficient number, since it is larger than the sum of its proper divisors (4625000084717).
13875000254139 is an equidigital number, since it uses as much as digits as its factorization.
13875000254139 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4625000084716.
The product of its (nonzero) digits is 907200, while the sum is 48.
The spelling of 13875000254139 in words is "thirteen trillion, eight hundred seventy-five billion, two hundred fifty-four thousand, one hundred thirty-nine".
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