Base | Representation |
---|---|
bin | 10100001100001111110… |
… | …010100010010011010011 |
3 | 11220122111000001210220021 |
4 | 110030033302202103103 |
5 | 140213140032430142 |
6 | 2541232103324311 |
7 | 202150342545451 |
oct | 24141762422323 |
9 | 4818430053807 |
10 | 1387539342547 |
11 | 4954a7870986 |
12 | 1a4ab8150697 |
13 | a0ac91b3797 |
14 | 4b22b7579d1 |
15 | 2615e248267 |
hex | 1430fca24d3 |
1387539342547 has 4 divisors (see below), whose sum is σ = 1389280296096. Its totient is φ = 1385798389000.
The previous prime is 1387539342521. The next prime is 1387539342557. The reversal of 1387539342547 is 7452439357831.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1387539342547 - 27 = 1387539342419 is a prime.
It is a super-2 number, since 2×13875393425472 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1387539342557) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 870475579 + ... + 870477172.
It is an arithmetic number, because the mean of its divisors is an integer number (347320074024).
Almost surely, 21387539342547 is an apocalyptic number.
1387539342547 is a deficient number, since it is larger than the sum of its proper divisors (1740953549).
1387539342547 is an equidigital number, since it uses as much as digits as its factorization.
1387539342547 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1740953548.
The product of its digits is 76204800, while the sum is 61.
The spelling of 1387539342547 in words is "one trillion, three hundred eighty-seven billion, five hundred thirty-nine million, three hundred forty-two thousand, five hundred forty-seven".
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