13877514025001 has 4 divisors (see below), whose sum is σ = 15139106209104. Its totient is φ = 12615921840900.

The previous prime is 13877514024973. The next prime is 13877514025007. The reversal of 13877514025001 is 10052041577831.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13877514025001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13877514025007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 630796092035 + ... + 630796092056.

It is an arithmetic number, because the mean of its divisors is an integer number (3784776552276).

Almost surely, 2^{13877514025001} is an apocalyptic number.

13877514025001 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13877514025001 is a deficient number, since it is larger than the sum of its proper divisors (1261592184103).

13877514025001 is a wasteful number, since it uses less digits than its factorization.

13877514025001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1261592184102.

The product of its (nonzero) digits is 235200, while the sum is 44.

The spelling of 13877514025001 in words is "thirteen trillion, eight hundred seventy-seven billion, five hundred fourteen million, twenty-five thousand, one".