Base | Representation |
---|---|
bin | 1100100111111000101110… |
… | …0001000111011000001011 |
3 | 1211010212002212012111010121 |
4 | 3021332023201013120023 |
5 | 3304344432243003441 |
6 | 45304033230524111 |
7 | 2631515655565066 |
oct | 311761341073013 |
9 | 54125085174117 |
10 | 13879380047371 |
11 | 4471237224a23 |
12 | 1681b00366637 |
13 | 798a874a6307 |
14 | 35daa0a678dd |
15 | 19107b7d7dd1 |
hex | c9f8b84760b |
13879380047371 has 8 divisors (see below), whose sum is σ = 13920211517184. Its totient is φ = 13838553367080.
The previous prime is 13879380047287. The next prime is 13879380047437. The reversal of 13879380047371 is 17374008397831.
13879380047371 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13879380047371 - 215 = 13879380014603 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13879380045371) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4648786 + ... + 7026376.
It is an arithmetic number, because the mean of its divisors is an integer number (1740026439648).
Almost surely, 213879380047371 is an apocalyptic number.
13879380047371 is a deficient number, since it is larger than the sum of its proper divisors (40831469813).
13879380047371 is a wasteful number, since it uses less digits than its factorization.
13879380047371 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2394761.
The product of its (nonzero) digits is 21337344, while the sum is 61.
The spelling of 13879380047371 in words is "thirteen trillion, eight hundred seventy-nine billion, three hundred eighty million, forty-seven thousand, three hundred seventy-one".
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