Base | Representation |
---|---|
bin | 1100101000010000010001… |
… | …0111011111001110110011 |
3 | 1211011110102111002002101112 |
4 | 3022010010113133032303 |
5 | 3310000404322042232 |
6 | 45311000443423535 |
7 | 2632131440046650 |
oct | 312040427371663 |
9 | 54143374062345 |
10 | 13885702534067 |
11 | 4473991098841 |
12 | 1683185824bab |
13 | 7995543140c0 |
14 | 360100620c27 |
15 | 1912eb8c24b2 |
hex | ca1045df3b3 |
13885702534067 has 16 divisors (see below), whose sum is σ = 17094163998912. Its totient is φ = 10983874406400.
The previous prime is 13885702534043. The next prime is 13885702534139. The reversal of 13885702534067 is 76043520758831.
13885702534067 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13885702534067 - 212 = 13885702529971 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13885702533997 and 13885702534015.
It is not an unprimeable number, because it can be changed into a prime (13885702534027) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17778878 + ... + 18543459.
It is an arithmetic number, because the mean of its divisors is an integer number (1068385249932).
Almost surely, 213885702534067 is an apocalyptic number.
13885702534067 is a deficient number, since it is larger than the sum of its proper divisors (3208461464845).
13885702534067 is a wasteful number, since it uses less digits than its factorization.
13885702534067 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 36326558.
The product of its (nonzero) digits is 33868800, while the sum is 59.
The spelling of 13885702534067 in words is "thirteen trillion, eight hundred eighty-five billion, seven hundred two million, five hundred thirty-four thousand, sixty-seven".
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