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1391002441921 = 2494355767247
BaseRepresentation
bin10100001111011110001…
…101001101100011000001
311220222102100111111011001
4110033132031031203001
5140242233111120141
62543003453452001
7202332223446211
oct24173615154301
94828370444131
101391002441921
11496a14684784
121a5703aa1001
13a122b800201
144b47966c241
15262b32b6a31
hex143de34d8c1

1391002441921 has 4 divisors (see below), whose sum is σ = 1391058234112. Its totient is φ = 1390946649732.

The previous prime is 1391002441889. The next prime is 1391002441951. The reversal of 1391002441921 is 1291442001931.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1391002441921 - 25 = 1391002441889 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1391002441951) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27858681 + ... + 27908566.

It is an arithmetic number, because the mean of its divisors is an integer number (347764558528).

Almost surely, 21391002441921 is an apocalyptic number.

It is an amenable number.

1391002441921 is a deficient number, since it is larger than the sum of its proper divisors (55792191).

1391002441921 is an equidigital number, since it uses as much as digits as its factorization.

1391002441921 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 55792190.

The product of its (nonzero) digits is 15552, while the sum is 37.

The spelling of 1391002441921 in words is "one trillion, three hundred ninety-one billion, two million, four hundred forty-one thousand, nine hundred twenty-one".

Divisors: 1 24943 55767247 1391002441921