Base | Representation |
---|---|
bin | 1000000110100111000… |
… | …1111110111010100011 |
3 | 111022100001001212102012 |
4 | 2001221301332322203 |
5 | 4240102144221112 |
6 | 143542011543135 |
7 | 13025562422153 |
oct | 2015161767243 |
9 | 438301055365 |
10 | 139213663907 |
11 | 540495361aa |
12 | 22b9245aaab |
13 | 101879b4576 |
14 | 6a4901c763 |
15 | 394bb98022 |
hex | 2069c7eea3 |
139213663907 has 4 divisors (see below), whose sum is σ = 139214463816. Its totient is φ = 139212864000.
The previous prime is 139213663829. The next prime is 139213663933. The reversal of 139213663907 is 709366312931.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 139213663907 - 212 = 139213659811 is a prime.
It is a super-2 number, since 2×1392136639072 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (139213663937) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16094 + ... + 527907.
It is an arithmetic number, because the mean of its divisors is an integer number (34803615954).
Almost surely, 2139213663907 is an apocalyptic number.
139213663907 is a deficient number, since it is larger than the sum of its proper divisors (799909).
139213663907 is an equidigital number, since it uses as much as digits as its factorization.
139213663907 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 799908.
The product of its (nonzero) digits is 1102248, while the sum is 50.
The spelling of 139213663907 in words is "one hundred thirty-nine billion, two hundred thirteen million, six hundred sixty-three thousand, nine hundred seven".
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