Base | Representation |
---|---|
bin | 1000000111101111000… |
… | …0011101101000100011 |
3 | 111100010001120022001221 |
4 | 2001323300131220203 |
5 | 4241211401132311 |
6 | 144031544035511 |
7 | 13036214050354 |
oct | 2017360355043 |
9 | 440101508057 |
10 | 139515255331 |
11 | 541937a7311 |
12 | 23057462b97 |
13 | 1020531b82a |
14 | 6a770c7d2b |
15 | 39683bd671 |
hex | 207bc1da23 |
139515255331 has 4 divisors (see below), whose sum is σ = 139534887600. Its totient is φ = 139495623064.
The previous prime is 139515255293. The next prime is 139515255409. The reversal of 139515255331 is 133552515931.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 139515255331 - 227 = 139381037603 is a prime.
It is a super-2 number, since 2×1395152553312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (139515255931) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9805471 + ... + 9819688.
It is an arithmetic number, because the mean of its divisors is an integer number (34883721900).
Almost surely, 2139515255331 is an apocalyptic number.
139515255331 is a deficient number, since it is larger than the sum of its proper divisors (19632269).
139515255331 is an equidigital number, since it uses as much as digits as its factorization.
139515255331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19632268.
The product of its digits is 303750, while the sum is 43.
The spelling of 139515255331 in words is "one hundred thirty-nine billion, five hundred fifteen million, two hundred fifty-five thousand, three hundred thirty-one".
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