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1396341952273 = 3145043288783
BaseRepresentation
bin10100010100011100011…
…101110100111100010001
311221111012110201201100201
4110110130131310330101
5140334202014433043
62545245354015201
7202611440521612
oct24243435647421
94844173651321
101396341952273
114992046a1954
121a6754117501
13a189cab15a8
144b824869c09
15264c6e33c4d
hex1451c774f11

1396341952273 has 4 divisors (see below), whose sum is σ = 1441385241088. Its totient is φ = 1351298663460.

The previous prime is 1396341952259. The next prime is 1396341952289. The reversal of 1396341952273 is 3722591436931.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1396341952273 - 229 = 1395805081361 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1396341952573) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22521644361 + ... + 22521644422.

It is an arithmetic number, because the mean of its divisors is an integer number (360346310272).

Almost surely, 21396341952273 is an apocalyptic number.

It is an amenable number.

1396341952273 is a deficient number, since it is larger than the sum of its proper divisors (45043288815).

1396341952273 is an equidigital number, since it uses as much as digits as its factorization.

1396341952273 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 45043288814.

The product of its digits is 7348320, while the sum is 55.

The spelling of 1396341952273 in words is "one trillion, three hundred ninety-six billion, three hundred forty-one million, nine hundred fifty-two thousand, two hundred seventy-three".

Divisors: 1 31 45043288783 1396341952273