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13967459897203 = 34477914051133
BaseRepresentation
bin1100101101000000110101…
…1111000100111101110011
31211110021110021222110102001
43023100031133010331303
53312320324213202303
645412321255434431
72641054451136151
oct313201537047563
954407407873361
1013967459897203
1144a5625a8784a
121696ba2085a17
137a418355b157
143640589343d1
151934d42c631d
hexcb40d7c4f73

13967459897203 has 4 divisors (see below), whose sum is σ = 13967467396128. Its totient is φ = 13967452398280.

The previous prime is 13967459897177. The next prime is 13967459897297. The reversal of 13967459897203 is 30279895476931.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 13967459897203 - 213 = 13967459889011 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13967454897203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1422225 + ... + 5473357.

It is an arithmetic number, because the mean of its divisors is an integer number (3491866849032).

It is a 1-persistent number, because it is pandigital, but 2⋅13967459897203 = 27934919794406 is not.

Almost surely, 213967459897203 is an apocalyptic number.

13967459897203 is a deficient number, since it is larger than the sum of its proper divisors (7498925).

13967459897203 is an equidigital number, since it uses as much as digits as its factorization.

13967459897203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7498924.

The product of its (nonzero) digits is 617258880, while the sum is 73.

The spelling of 13967459897203 in words is "thirteen trillion, nine hundred sixty-seven billion, four hundred fifty-nine million, eight hundred ninety-seven thousand, two hundred three".

Divisors: 1 3447791 4051133 13967459897203