Base | Representation |
---|---|
bin | 1100101101000000110101… |
… | …1111000100111101110011 |
3 | 1211110021110021222110102001 |
4 | 3023100031133010331303 |
5 | 3312320324213202303 |
6 | 45412321255434431 |
7 | 2641054451136151 |
oct | 313201537047563 |
9 | 54407407873361 |
10 | 13967459897203 |
11 | 44a5625a8784a |
12 | 1696ba2085a17 |
13 | 7a418355b157 |
14 | 3640589343d1 |
15 | 1934d42c631d |
hex | cb40d7c4f73 |
13967459897203 has 4 divisors (see below), whose sum is σ = 13967467396128. Its totient is φ = 13967452398280.
The previous prime is 13967459897177. The next prime is 13967459897297. The reversal of 13967459897203 is 30279895476931.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 13967459897203 - 213 = 13967459889011 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13967454897203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1422225 + ... + 5473357.
It is an arithmetic number, because the mean of its divisors is an integer number (3491866849032).
It is a 1-persistent number, because it is pandigital, but 2⋅13967459897203 = 27934919794406 is not.
Almost surely, 213967459897203 is an apocalyptic number.
13967459897203 is a deficient number, since it is larger than the sum of its proper divisors (7498925).
13967459897203 is an equidigital number, since it uses as much as digits as its factorization.
13967459897203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7498924.
The product of its (nonzero) digits is 617258880, while the sum is 73.
The spelling of 13967459897203 in words is "thirteen trillion, nine hundred sixty-seven billion, four hundred fifty-nine million, eight hundred ninety-seven thousand, two hundred three".
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