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1397009433 = 32909160079
BaseRepresentation
bin101001101000100…
…1010110000011001
310121100201102200010
41103101022300121
510330113300213
6350342432133
746422245541
oct12321126031
93540642603
101397009433
11657636956
1232ba32649
13193572501
14d3774321
15829a3ac3
hex5344ac19

1397009433 has 8 divisors (see below), whose sum is σ = 1863331200. Its totient is φ = 931013648.

The previous prime is 1397009417. The next prime is 1397009473. The reversal of 1397009433 is 3349007931.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1397009433 - 24 = 1397009417 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1397009391 and 1397009400.

It is not an unprimeable number, because it can be changed into a prime (1397009473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 71313 + ... + 88766.

It is an arithmetic number, because the mean of its divisors is an integer number (232916400).

Almost surely, 21397009433 is an apocalyptic number.

It is an amenable number.

1397009433 is a deficient number, since it is larger than the sum of its proper divisors (466321767).

1397009433 is a wasteful number, since it uses less digits than its factorization.

1397009433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 162991.

The product of its (nonzero) digits is 61236, while the sum is 39.

The square root of 1397009433 is about 37376.5893708883. The cubic root of 1397009433 is about 1117.8918232234.

The spelling of 1397009433 in words is "one billion, three hundred ninety-seven million, nine thousand, four hundred thirty-three".

Divisors: 1 3 2909 8727 160079 480237 465669811 1397009433