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13970443 = 25795417
BaseRepresentation
bin110101010010…
…110000001011
3222021202211211
4311102300023
512034023233
61215233551
7226514104
oct65226013
928252754
1013970443
117982223
1248188b7
132b81b46
141bd93ab
15135e5cd
hexd52c0b

13970443 has 4 divisors (see below), whose sum is σ = 13978440. Its totient is φ = 13962448.

The previous prime is 13970401. The next prime is 13970459. The reversal of 13970443 is 34407931.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 13970443 - 213 = 13962251 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13970483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 130 + ... + 5287.

It is an arithmetic number, because the mean of its divisors is an integer number (3494610).

Almost surely, 213970443 is an apocalyptic number.

13970443 is a deficient number, since it is larger than the sum of its proper divisors (7997).

13970443 is an equidigital number, since it uses as much as digits as its factorization.

13970443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7996.

The product of its (nonzero) digits is 9072, while the sum is 31.

The square root of 13970443 is about 3737.7055796304. The cubic root of 13970443 is about 240.8444960231.

The spelling of 13970443 in words is "thirteen million, nine hundred seventy thousand, four hundred forty-three".

Divisors: 1 2579 5417 13970443