139994843 has 4 divisors (see below), whose sum is σ = 140094240. Its totient is φ = 139895448.

The previous prime is 139994837. The next prime is 139994857. The reversal of 139994843 is 348499931.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-139994843 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 139994791 and 139994800.

It is not an unprimeable number, because it can be changed into a prime (139994893) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47555 + ... + 50412.

It is an arithmetic number, because the mean of its divisors is an integer number (35023560).

Almost surely, 2^139994843 is an apocalyptic number.

139994843 is a deficient number, since it is larger than the sum of its proper divisors (99397).

139994843 is an equidigital number, since it uses as much as digits as its factorization.

139994843 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 99396.

The product of its digits is 839808, while the sum is 50.

The square root of 139994843 is about 11831.9416411678. The cubic root of 139994843 is about 519.2430344659.

The spelling of 139994843 in words is "one hundred thirty-nine million, nine hundred ninety-four thousand, eight hundred forty-three".