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13999970473 = 83531676041
BaseRepresentation
bin11010000100111011…
…01001100010101001
31100010200102012001221
431002131221202221
5212132443023343
610233111542041
71003634533306
oct150235514251
940120365057
1013999970473
115a34689035
12286868a921
1314215cb5c8
1496b4aa0ad
1556e1295ed
hex3427698a9

13999970473 has 4 divisors (see below), whose sum is σ = 14001654868. Its totient is φ = 13998286080.

The previous prime is 13999970437. The next prime is 13999970477. The reversal of 13999970473 is 37407999931.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4746107664 + 9253862809 = 68892^2 + 96197^2 .

It is a cyclic number.

It is not a de Polignac number, because 13999970473 - 29 = 13999969961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13999970477) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 829668 + ... + 846373.

It is an arithmetic number, because the mean of its divisors is an integer number (3500413717).

Almost surely, 213999970473 is an apocalyptic number.

It is an amenable number.

13999970473 is a deficient number, since it is larger than the sum of its proper divisors (1684395).

13999970473 is an equidigital number, since it uses as much as digits as its factorization.

13999970473 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1684394.

The product of its (nonzero) digits is 11573604, while the sum is 61.

The spelling of 13999970473 in words is "thirteen billion, nine hundred ninety-nine million, nine hundred seventy thousand, four hundred seventy-three".

Divisors: 1 8353 1676041 13999970473