Base | Representation |
---|---|
bin | 11010000100111011… |
… | …01001100010101001 |
3 | 1100010200102012001221 |
4 | 31002131221202221 |
5 | 212132443023343 |
6 | 10233111542041 |
7 | 1003634533306 |
oct | 150235514251 |
9 | 40120365057 |
10 | 13999970473 |
11 | 5a34689035 |
12 | 286868a921 |
13 | 14215cb5c8 |
14 | 96b4aa0ad |
15 | 56e1295ed |
hex | 3427698a9 |
13999970473 has 4 divisors (see below), whose sum is σ = 14001654868. Its totient is φ = 13998286080.
The previous prime is 13999970437. The next prime is 13999970477. The reversal of 13999970473 is 37407999931.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 4746107664 + 9253862809 = 68892^2 + 96197^2 .
It is a cyclic number.
It is not a de Polignac number, because 13999970473 - 29 = 13999969961 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13999970477) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 829668 + ... + 846373.
It is an arithmetic number, because the mean of its divisors is an integer number (3500413717).
Almost surely, 213999970473 is an apocalyptic number.
It is an amenable number.
13999970473 is a deficient number, since it is larger than the sum of its proper divisors (1684395).
13999970473 is an equidigital number, since it uses as much as digits as its factorization.
13999970473 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1684394.
The product of its (nonzero) digits is 11573604, while the sum is 61.
The spelling of 13999970473 in words is "thirteen billion, nine hundred ninety-nine million, nine hundred seventy thousand, four hundred seventy-three".
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