14000000000001 has 4 divisors (see below), whose sum is σ = 18666666666672. Its totient is φ = 9333333333332.

The previous prime is 13999999999963. The next prime is 14000000000003. The reversal of 14000000000001 is 10000000000041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14000000000001 - 2¹⁷ = 13999999868929 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14000000000001.

It is not an unprimeable number, because it can be changed into a prime (14000000000003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2333333333331 + ... + 2333333333336.

It is an arithmetic number, because the mean of its divisors is an integer number (4666666666668).

Almost surely, 2^{14000000000001} is an apocalyptic number.

It is an amenable number.

14000000000001 is a deficient number, since it is larger than the sum of its proper divisors (4666666666671).

14000000000001 is an equidigital number, since it uses as much as digits as its factorization.

14000000000001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4666666666670.

The product of its (nonzero) digits is 4, while the sum is 6.

Adding to 14000000000001 its reverse (10000000000041), we get a palindrome (24000000000042).

The spelling of 14000000000001 in words is "fourteen trillion, one", and thus it is an aban number.