14000241323 has 4 divisors (see below), whose sum is σ = 14000511000. Its totient is φ = 13999971648.

The previous prime is 14000241317. The next prime is 14000241331. The reversal of 14000241323 is 32314200041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14000241323 - 2¹² = 14000237227 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14000241295 and 14000241304.

It is not an unprimeable number, because it can be changed into a prime (14000241223) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29573 + ... + 169926.

It is an arithmetic number, because the mean of its divisors is an integer number (3500127750).

Almost surely, 2^14000241323 is an apocalyptic number.

14000241323 is a deficient number, since it is larger than the sum of its proper divisors (269677).

14000241323 is an equidigital number, since it uses as much as digits as its factorization.

14000241323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 269676.

The product of its (nonzero) digits is 576, while the sum is 20.

Adding to 14000241323 its reverse (32314200041), we get a palindrome (46314441364).

The spelling of 14000241323 in words is "fourteen billion, two hundred forty-one thousand, three hundred twenty-three".