Search a number
-
+
14001004241 = 72000143463
BaseRepresentation
bin11010000101000011…
…00101111011010001
31100010202100201010122
431002201211323101
5212133224113431
610233150040025
71003646400230
oct150241457321
940122321118
1014001004241
115a35224794
122868aa9015
1314218a0cc3
1496b698b17
1556e280a7b
hex342865ed1

14001004241 has 4 divisors (see below), whose sum is σ = 16001147712. Its totient is φ = 12000860772.

The previous prime is 14001004231. The next prime is 14001004261. The reversal of 14001004241 is 14240010041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14240010041 = 29491034829.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14001004241 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (14001004231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1000071725 + ... + 1000071738.

It is an arithmetic number, because the mean of its divisors is an integer number (4000286928).

Almost surely, 214001004241 is an apocalyptic number.

It is an amenable number.

14001004241 is a deficient number, since it is larger than the sum of its proper divisors (2000143471).

14001004241 is an equidigital number, since it uses as much as digits as its factorization.

14001004241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2000143470.

The product of its (nonzero) digits is 128, while the sum is 17.

Adding to 14001004241 its reverse (14240010041), we get a palindrome (28241014282).

The spelling of 14001004241 in words is "fourteen billion, one million, four thousand, two hundred forty-one".

Divisors: 1 7 2000143463 14001004241