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14001132224411 = 62873222689107
BaseRepresentation
bin1100101110111110010010…
…0000110011111110011011
31211120111100222101220122222
43023233210200303332123
53313343304322140121
645440010434334255
72643356052165263
oct313574440637633
954514328356588
1014001132224411
11450893514a642
1216a161aa2a38b
137a73bb6a8217
143659309987a3
151943054ec0ab
hexcbbe4833f9b

14001132224411 has 4 divisors (see below), whose sum is σ = 14001354976392. Its totient is φ = 14000909472432.

The previous prime is 14001132224377. The next prime is 14001132224459. The reversal of 14001132224411 is 11442223110041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14001132224411 - 234 = 13983952355227 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14001134224411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 111281681 + ... + 111407426.

It is an arithmetic number, because the mean of its divisors is an integer number (3500338744098).

Almost surely, 214001132224411 is an apocalyptic number.

14001132224411 is a deficient number, since it is larger than the sum of its proper divisors (222751981).

14001132224411 is an equidigital number, since it uses as much as digits as its factorization.

14001132224411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 222751980.

The product of its (nonzero) digits is 1536, while the sum is 26.

Adding to 14001132224411 its reverse (11442223110041), we get a palindrome (25443355334452).

The spelling of 14001132224411 in words is "fourteen trillion, one billion, one hundred thirty-two million, two hundred twenty-four thousand, four hundred eleven".

Divisors: 1 62873 222689107 14001132224411