140012303424113 has 4 divisors (see below), whose sum is σ = 140871274610928. Its totient is φ = 139153332237300.

The previous prime is 140012303424107. The next prime is 140012303424121. The reversal of 140012303424113 is 311424303210041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-140012303424113 is a prime.

It is a super-2 number, since 2×140012303424113² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140012303424193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 429485593163 + ... + 429485593488.

It is an arithmetic number, because the mean of its divisors is an integer number (35217818652732).

Almost surely, 2^{140012303424113} is an apocalyptic number.

It is an amenable number.

140012303424113 is a deficient number, since it is larger than the sum of its proper divisors (858971186815).

140012303424113 is an equidigital number, since it uses as much as digits as its factorization.

140012303424113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 858971186814.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 140012303424113 its reverse (311424303210041), we get a palindrome (451436606634154).

The spelling of 140012303424113 in words is "one hundred forty trillion, twelve billion, three hundred three million, four hundred twenty-four thousand, one hundred thirteen".