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140012334041 = 311450200431
BaseRepresentation
bin1000001001100101100…
…0101010101111011001
3111101101200220111212112
42002121120222233121
54243221124142131
6144153142122105
713054431126416
oct2023130525731
9441350814775
10140012334041
1154419348968
1223175a20335
13102842c0048
146ac311d10d
153996d5b02b
hex209962abd9

140012334041 has 4 divisors (see below), whose sum is σ = 140462534784. Its totient is φ = 139562133300.

The previous prime is 140012334031. The next prime is 140012334083. The reversal of 140012334041 is 140433210041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140012334041 - 222 = 140008139737 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140012333998 and 140012334016.

It is not an unprimeable number, because it can be changed into a prime (140012334001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 225099905 + ... + 225100526.

It is an arithmetic number, because the mean of its divisors is an integer number (35115633696).

Almost surely, 2140012334041 is an apocalyptic number.

It is an amenable number.

140012334041 is a deficient number, since it is larger than the sum of its proper divisors (450200743).

140012334041 is an equidigital number, since it uses as much as digits as its factorization.

140012334041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 450200742.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 140012334041 its reverse (140433210041), we get a palindrome (280445544082).

The spelling of 140012334041 in words is "one hundred forty billion, twelve million, three hundred thirty-four thousand, forty-one".

Divisors: 1 311 450200431 140012334041