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140013003001411 = 178236059000083
BaseRepresentation
bin11111110101011101010001…
…010011101100111001000011
3200100202010000220200110020001
4133311131101103230321003
5121322433112232021121
61213441030254300431
741330414511004141
oct3765352123547103
9610663026613201
10140013003001411
11406811aa076701
121385355b4b7717
1360182285c3587
1426809461d8591
15112c0d5d32991
hex7f57514ece43

140013003001411 has 4 divisors (see below), whose sum is σ = 148249062001512. Its totient is φ = 131776944001312.

The previous prime is 140013003001387. The next prime is 140013003001483. The reversal of 140013003001411 is 114100300310041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 140013003001411 - 219 = 140013002477123 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140013004001411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4118029500025 + ... + 4118029500058.

It is an arithmetic number, because the mean of its divisors is an integer number (37062265500378).

Almost surely, 2140013003001411 is an apocalyptic number.

140013003001411 is a deficient number, since it is larger than the sum of its proper divisors (8236059000101).

140013003001411 is an equidigital number, since it uses as much as digits as its factorization.

140013003001411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8236059000100.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 140013003001411 its reverse (114100300310041), we get a palindrome (254113303311452).

The spelling of 140013003001411 in words is "one hundred forty trillion, thirteen billion, three million, one thousand, four hundred eleven".

Divisors: 1 17 8236059000083 140013003001411