14001300420113 has 4 divisors (see below), whose sum is σ = 14738210968560. Its totient is φ = 13264389871668.

The previous prime is 14001300420109. The next prime is 14001300420187. The reversal of 14001300420113 is 31102400310041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14001300420113 - 2² = 14001300420109 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14001300420103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 368455274195 + ... + 368455274232.

It is an arithmetic number, because the mean of its divisors is an integer number (3684552742140).

Almost surely, 2^{14001300420113} is an apocalyptic number.

It is an amenable number.

14001300420113 is a deficient number, since it is larger than the sum of its proper divisors (736910548447).

14001300420113 is an equidigital number, since it uses as much as digits as its factorization.

14001300420113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 736910548446.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 14001300420113 its reverse (31102400310041), we get a palindrome (45103700730154).

The spelling of 14001300420113 in words is "fourteen trillion, one billion, three hundred million, four hundred twenty thousand, one hundred thirteen".