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140013004430003 = 181773552510663
BaseRepresentation
bin11111110101011101010001…
…011001001001101010110011
3200100202010001000101000212212
4133311131101121021222303
5121322433113113230003
61213441030345042335
741330414526104135
oct3765352131115263
9610663030330785
10140013004430003
11406811aa961a61
121385355ba863ab
1360182289a38b3
14268094648b055
15112c0d6015dd8
hex7f5751649ab3

140013004430003 has 4 divisors (see below), whose sum is σ = 140786556940848. Its totient is φ = 139239451919160.

The previous prime is 140013004429981. The next prime is 140013004430041. The reversal of 140013004430003 is 300034400310041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 140013004430003 - 26 = 140013004429939 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140013004430053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 386776255151 + ... + 386776255512.

It is an arithmetic number, because the mean of its divisors is an integer number (35196639235212).

Almost surely, 2140013004430003 is an apocalyptic number.

140013004430003 is a deficient number, since it is larger than the sum of its proper divisors (773552510845).

140013004430003 is an equidigital number, since it uses as much as digits as its factorization.

140013004430003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 773552510844.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 140013004430003 its reverse (300034400310041), we get a palindrome (440047404740044).

The spelling of 140013004430003 in words is "one hundred forty trillion, thirteen billion, four million, four hundred thirty thousand, three".

Divisors: 1 181 773552510663 140013004430003