Base | Representation |
---|---|
bin | 11111110101011101010001… |
… | …011001001001101010110011 |
3 | 200100202010001000101000212212 |
4 | 133311131101121021222303 |
5 | 121322433113113230003 |
6 | 1213441030345042335 |
7 | 41330414526104135 |
oct | 3765352131115263 |
9 | 610663030330785 |
10 | 140013004430003 |
11 | 406811aa961a61 |
12 | 1385355ba863ab |
13 | 60182289a38b3 |
14 | 268094648b055 |
15 | 112c0d6015dd8 |
hex | 7f5751649ab3 |
140013004430003 has 4 divisors (see below), whose sum is σ = 140786556940848. Its totient is φ = 139239451919160.
The previous prime is 140013004429981. The next prime is 140013004430041. The reversal of 140013004430003 is 300034400310041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 140013004430003 - 26 = 140013004429939 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (140013004430053) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 386776255151 + ... + 386776255512.
It is an arithmetic number, because the mean of its divisors is an integer number (35196639235212).
Almost surely, 2140013004430003 is an apocalyptic number.
140013004430003 is a deficient number, since it is larger than the sum of its proper divisors (773552510845).
140013004430003 is an equidigital number, since it uses as much as digits as its factorization.
140013004430003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 773552510844.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 140013004430003 its reverse (300034400310041), we get a palindrome (440047404740044).
The spelling of 140013004430003 in words is "one hundred forty trillion, thirteen billion, four million, four hundred thirty thousand, three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •