Base | Representation |
---|---|
bin | 11111110101011101010111… |
… | …010110101010001110110011 |
3 | 200100202010021222120002010211 |
4 | 133311131113112222032303 |
5 | 121322433314214041433 |
6 | 1213441044320404551 |
7 | 41330420152141156 |
oct | 3765352726521663 |
9 | 610663258502124 |
10 | 140013104440243 |
11 | 40681251360151 |
12 | 13853589476757 |
13 | 601824361bc58 |
14 | 2680955881c9d |
15 | 112c0debbd8cd |
hex | 7f57575aa3b3 |
140013104440243 has 4 divisors (see below), whose sum is σ = 140388474693808. Its totient is φ = 139637734186680.
The previous prime is 140013104440213. The next prime is 140013104440277. The reversal of 140013104440243 is 342044401310041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 140013104440243 - 221 = 140013102343091 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (140013104440213) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 187685126223 + ... + 187685126968.
It is an arithmetic number, because the mean of its divisors is an integer number (35097118673452).
Almost surely, 2140013104440243 is an apocalyptic number.
140013104440243 is a deficient number, since it is larger than the sum of its proper divisors (375370253565).
140013104440243 is an equidigital number, since it uses as much as digits as its factorization.
140013104440243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 375370253564.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 140013104440243 its reverse (342044401310041), we get a palindrome (482057505750284).
The spelling of 140013104440243 in words is "one hundred forty trillion, thirteen billion, one hundred four million, four hundred forty thousand, two hundred forty-three".
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