Base | Representation |
---|---|
bin | 11111110101011101011111… |
… | …000010110001001001001011 |
3 | 200100202010121222022010012122 |
4 | 133311131133002301021023 |
5 | 121322434100230142103 |
6 | 1213441105205401455 |
7 | 41330423306510525 |
oct | 3765353702611113 |
9 | 610663558263178 |
10 | 140013233443403 |
11 | 40681308161131 |
12 | 1385360470928b |
13 | 6018264278a98 |
14 | 2680968a62a15 |
15 | 112c0eb1a1b38 |
hex | 7f575f0b124b |
140013233443403 has 4 divisors (see below), whose sum is σ = 140053594713360. Its totient is φ = 139972872173448.
The previous prime is 140013233443379. The next prime is 140013233443451. The reversal of 140013233443403 is 304344332310041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 140013233443403 - 218 = 140013233181259 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (140013233443703) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20180629775 + ... + 20180636712.
It is an arithmetic number, because the mean of its divisors is an integer number (35013398678340).
Almost surely, 2140013233443403 is an apocalyptic number.
140013233443403 is a deficient number, since it is larger than the sum of its proper divisors (40361269957).
140013233443403 is an equidigital number, since it uses as much as digits as its factorization.
140013233443403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 40361269956.
The product of its (nonzero) digits is 124416, while the sum is 35.
Adding to 140013233443403 its reverse (304344332310041), we get a palindrome (444357565753444).
The spelling of 140013233443403 in words is "one hundred forty trillion, thirteen billion, two hundred thirty-three million, four hundred forty-three thousand, four hundred three".
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