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1400133100003 = 11127284827273
BaseRepresentation
bin10100010111111110011…
…011111010000111100011
311221211222200102222100121
4110113332123322013203
5140414433033200003
62551113503301111
7203104413661501
oct24277633720743
94854880388317
101400133100003
1149a87a6a72a0
121a74318aa797
13a2055369681
144baa4175671
1526649ba1cbd
hex145fe6fa1e3

1400133100003 has 4 divisors (see below), whose sum is σ = 1527417927288. Its totient is φ = 1272848272720.

The previous prime is 1400133099977. The next prime is 1400133100019. The reversal of 1400133100003 is 3000013310041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1400133100003 - 237 = 1262694146531 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1400133100003.

It is not an unprimeable number, because it can be changed into a prime (1400133100043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 63642413626 + ... + 63642413647.

It is an arithmetic number, because the mean of its divisors is an integer number (381854481822).

Almost surely, 21400133100003 is an apocalyptic number.

1400133100003 is a deficient number, since it is larger than the sum of its proper divisors (127284827285).

1400133100003 is a wasteful number, since it uses less digits than its factorization.

1400133100003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 127284827284.

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 1400133100003 its reverse (3000013310041), we get a palindrome (4400146410044).

The spelling of 1400133100003 in words is "one trillion, four hundred billion, one hundred thirty-three million, one hundred thousand, three".

Divisors: 1 11 127284827273 1400133100003