1400133121 has 4 divisors (see below), whose sum is σ = 1405943044. Its totient is φ = 1394323200.

The previous prime is 1400133113. The next prime is 1400133127. The reversal of 1400133121 is 1213310041.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1213310041 = 113 ⋅10737257.

It can be written as a sum of positive squares in 2 ways, for example, as 1282714225 + 117418896 = 35815^2 + 10836^2 .

It is a cyclic number.

It is not a de Polignac number, because 1400133121 - 2³ = 1400133113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1400133095 and 1400133104.

It is not an unprimeable number, because it can be changed into a prime (1400133127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2904600 + ... + 2905081.

It is an arithmetic number, because the mean of its divisors is an integer number (351485761).

Almost surely, 2^1400133121 is an apocalyptic number.

It is an amenable number.

1400133121 is a deficient number, since it is larger than the sum of its proper divisors (5809923).

1400133121 is an equidigital number, since it uses as much as digits as its factorization.

1400133121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5809922.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 1400133121 is about 37418.3527296432. The cubic root of 1400133121 is about 1118.7243983363.

Adding to 1400133121 its reverse (1213310041), we get a palindrome (2613443162).

The spelling of 1400133121 in words is "one billion, four hundred million, one hundred thirty-three thousand, one hundred twenty-one".