1400133220121 has 4 divisors (see below), whose sum is σ = 1400604489744. Its totient is φ = 1399661950500.

The previous prime is 1400133220117. The next prime is 1400133220141. The reversal of 1400133220121 is 1210223310041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1400133220121 - 2² = 1400133220117 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1400133220093 and 1400133220102.

It is not an unprimeable number, because it can be changed into a prime (1400133220141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 235630355 + ... + 235636296.

It is an arithmetic number, because the mean of its divisors is an integer number (350151122436).

Almost surely, 2^{1400133220121} is an apocalyptic number.

It is an amenable number.

1400133220121 is a deficient number, since it is larger than the sum of its proper divisors (471269623).

1400133220121 is an equidigital number, since it uses as much as digits as its factorization.

1400133220121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 471269622.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 1400133220121 its reverse (1210223310041), we get a palindrome (2610356530162).

The spelling of 1400133220121 in words is "one trillion, four hundred billion, one hundred thirty-three million, two hundred twenty thousand, one hundred twenty-one".