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14002112433 = 316632806597
BaseRepresentation
bin11010000101001011…
…10100011110110001
31100010211110000021210
431002211310132301
5212134020044213
610233225510333
71003661664141
oct150245643661
940124400253
1014002112433
115a35911351
1228693423a9
131421b9b53a
1496b8a6921
1556e3ee0c3
hex3429747b1

14002112433 has 8 divisors (see below), whose sum is σ = 18680716288. Its totient is φ = 9329125104.

The previous prime is 14002112381. The next prime is 14002112459. The reversal of 14002112433 is 33421120041.

14002112433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14002112433 - 28 = 14002112177 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14002112483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1398310 + ... + 1408287.

It is an arithmetic number, because the mean of its divisors is an integer number (2335089536).

Almost surely, 214002112433 is an apocalyptic number.

It is an amenable number.

14002112433 is a deficient number, since it is larger than the sum of its proper divisors (4678603855).

14002112433 is a wasteful number, since it uses less digits than its factorization.

14002112433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2808263.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 14002112433 its reverse (33421120041), we get a palindrome (47423232474).

The spelling of 14002112433 in words is "fourteen billion, two million, one hundred twelve thousand, four hundred thirty-three".

Divisors: 1 3 1663 4989 2806597 8419791 4667370811 14002112433