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14002203000403 = 311104942920077
BaseRepresentation
bin1100101111000010010001…
…0101011111111001010011
31211120121010121020222012001
43023300210111133321103
53313403002432003103
645440305005014431
72643424433504212
oct313604425377123
954517117228161
1014002203000403
114509334614482
1216a1879554417
137a752c496197
143659d2c8b079
1519436950e01d
hexcbc2455fe53

14002203000403 has 8 divisors (see below), whose sum is σ = 14060617552800. Its totient is φ = 13943874290880.

The previous prime is 14002203000389. The next prime is 14002203000437. The reversal of 14002203000403 is 30400030220041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14002203000403 - 29 = 14002202999891 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14002203001403) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21133800 + ... + 21786277.

It is an arithmetic number, because the mean of its divisors is an integer number (1757577194100).

Almost surely, 214002203000403 is an apocalyptic number.

14002203000403 is a deficient number, since it is larger than the sum of its proper divisors (58414552397).

14002203000403 is a wasteful number, since it uses less digits than its factorization.

14002203000403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 42921437.

The product of its (nonzero) digits is 576, while the sum is 19.

Adding to 14002203000403 its reverse (30400030220041), we get a palindrome (44402233220444).

The spelling of 14002203000403 in words is "fourteen trillion, two billion, two hundred three million, four hundred three", and thus it is an aban number.

Divisors: 1 311 1049 326239 42920077 13348143947 45023160773 14002203000403