Base | Representation |
---|---|
bin | 10100011000000101011… |
… | …110110110011000011001 |
3 | 11221212021220212202020102 |
4 | 110120011132312120121 |
5 | 140420203313433031 |
6 | 2551133325105145 |
7 | 203110350524030 |
oct | 24300536663031 |
9 | 4855256782212 |
10 | 1400251311641 |
11 | 49a9303a7466 |
12 | 1a74653b81b5 |
13 | a20739b85a0 |
14 | 4bab5b47717 |
15 | 266552527cb |
hex | 146057b6619 |
1400251311641 has 16 divisors (see below), whose sum is σ = 1746994268544. Its totient is φ = 1092714551424.
The previous prime is 1400251311421. The next prime is 1400251311707. The reversal of 1400251311641 is 1461131520041.
It is a cyclic number.
It is not a de Polignac number, because 1400251311641 - 218 = 1400251049497 is a prime.
It is a super-2 number, since 2×14002513116412 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1400221311641) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 105386351 + ... + 105399636.
It is an arithmetic number, because the mean of its divisors is an integer number (109187141784).
Almost surely, 21400251311641 is an apocalyptic number.
It is an amenable number.
1400251311641 is a deficient number, since it is larger than the sum of its proper divisors (346742956903).
1400251311641 is a wasteful number, since it uses less digits than its factorization.
1400251311641 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 210786080.
The product of its (nonzero) digits is 2880, while the sum is 29.
Adding to 1400251311641 its reverse (1461131520041), we get a palindrome (2861382831682).
The spelling of 1400251311641 in words is "one trillion, four hundred billion, two hundred fifty-one million, three hundred eleven thousand, six hundred forty-one".
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