Base | Representation |
---|---|
bin | 11111110101101111000101… |
… | …100100000001000001010011 |
3 | 200100210221102010201112110111 |
4 | 133311233011210001001103 |
5 | 121323241302111220103 |
6 | 1213453512435142151 |
7 | 41331662542622224 |
oct | 3765570544010123 |
9 | 610727363645414 |
10 | 140032133304403 |
11 | 4068932669046a |
12 | 138571ba144957 |
13 | 6019c86a546a2 |
14 | 268183cbb124b |
15 | 112c85555a86d |
hex | 7f5bc5901053 |
140032133304403 has 4 divisors (see below), whose sum is σ = 140032160467200. Its totient is φ = 140032106141608.
The previous prime is 140032133304337. The next prime is 140032133304407. The reversal of 140032133304403 is 304403331230041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 140032133304403 - 29 = 140032133303891 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (140032133304407) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3206803 + ... + 17039596.
It is an arithmetic number, because the mean of its divisors is an integer number (35008040116800).
Almost surely, 2140032133304403 is an apocalyptic number.
140032133304403 is a deficient number, since it is larger than the sum of its proper divisors (27162797).
140032133304403 is an equidigital number, since it uses as much as digits as its factorization.
140032133304403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 27162796.
The product of its (nonzero) digits is 31104, while the sum is 31.
Adding to 140032133304403 its reverse (304403331230041), we get a palindrome (444435464534444).
The spelling of 140032133304403 in words is "one hundred forty trillion, thirty-two billion, one hundred thirty-three million, three hundred four thousand, four hundred three".
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