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14003254354147 = 62712233017757
BaseRepresentation
bin1100101111000110001100…
…0000000110000011100011
31211120200211212120021101121
43023301203000012003203
53313412131103313042
645441001203113111
72643462461041402
oct313614300060343
954520755507347
1014003254354147
114509824023073
1216a1b11672797
137a76692439a6
14365a92765639
151943cb986367
hexcbc630060e3

14003254354147 has 4 divisors (see below), whose sum is σ = 14005487378176. Its totient is φ = 14001021330120.

The previous prime is 14003254354139. The next prime is 14003254354181. The reversal of 14003254354147 is 74145345230041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14003254354147 - 23 = 14003254354139 is a prime.

It is a super-2 number, since 2×140032543541472 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14003254354547) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1116502608 + ... + 1116515149.

It is an arithmetic number, because the mean of its divisors is an integer number (3501371844544).

Almost surely, 214003254354147 is an apocalyptic number.

14003254354147 is a deficient number, since it is larger than the sum of its proper divisors (2233024029).

14003254354147 is an equidigital number, since it uses as much as digits as its factorization.

14003254354147 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2233024028.

The product of its (nonzero) digits is 806400, while the sum is 43.

Adding to 14003254354147 its reverse (74145345230041), we get a palindrome (88148599584188).

The spelling of 14003254354147 in words is "fourteen trillion, three billion, two hundred fifty-four million, three hundred fifty-four thousand, one hundred forty-seven".

Divisors: 1 6271 2233017757 14003254354147