Base | Representation |
---|---|
bin | 1000001001101011000… |
… | …0101100110110010001 |
3 | 111101110022022221222111 |
4 | 2002122300230312101 |
5 | 4243243031130340 |
6 | 144155324505321 |
7 | 13055131233244 |
oct | 2023260546621 |
9 | 441408287874 |
10 | 140035411345 |
11 | 54430380215 |
12 | 231816ab241 |
13 | 1028901005b |
14 | 6ac620925b |
15 | 3998db8aea |
hex | 209ac2cd91 |
140035411345 has 4 divisors (see below), whose sum is σ = 168042493620. Its totient is φ = 112028329072.
The previous prime is 140035411337. The next prime is 140035411379. The reversal of 140035411345 is 543114530041.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 543114530041 = 51427 ⋅10560883.
It can be written as a sum of positive squares in 2 ways, for example, as 67941550336 + 72093861009 = 260656^2 + 268503^2 .
It is a cyclic number.
It is not a de Polignac number, because 140035411345 - 23 = 140035411337 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14003541130 + ... + 14003541139.
It is an arithmetic number, because the mean of its divisors is an integer number (42010623405).
Almost surely, 2140035411345 is an apocalyptic number.
It is an amenable number.
140035411345 is a deficient number, since it is larger than the sum of its proper divisors (28007082275).
140035411345 is an equidigital number, since it uses as much as digits as its factorization.
140035411345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28007082274.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 140035411345 its reverse (543114530041), we get a palindrome (683149941386).
The spelling of 140035411345 in words is "one hundred forty billion, thirty-five million, four hundred eleven thousand, three hundred forty-five".
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